\[\sin x=\dfrac{\sqrt{3}}{2}\\\Leftrightarrow \sin x=\sin\dfrac{\pi}{3}\\\Leftrightarrow \left[\begin{array}{I}x=\dfrac{\pi}{3}+k2\pi\\x=\pi-\dfrac{\pi}{3}+k2\pi\end{array}\right.\\\Leftrightarrow \left[\begin{array}{I}x=\dfrac{\pi}{3}+k2\pi\\x=\dfrac{2\pi}{3}+k2\pi.\end{array}\right.\quad[k\in\mathbb{Z}]\\\text{Vậy S=}\left\{\dfrac{\pi}{3}+k2\pi;\dfrac{2\pi}{3}+k2\pi\Big|k\in\mathbb{Z}\right\}.\]
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