A dihybrid cross between a green wrinkled pea seed and a yellow smooth pea seed

Half of the gametes get a dominant S and a dominant Y allele; the other half of the gametes get a recessive s and a recessive y allele.

Both parents produce 25% each of SY, Sy, sY, and sy.

(Review the tutorials for problems #1 and problem #4 if necessary).

Since each Parent produces 4 different combinations of alleles in the gametes, draw a 4 square by 4 square punnett square.

List the gametes for Parent 1 along one edge of the punnett square.

List the gametes for Parent 2 along one edge of the punnett square.

Fill out the squares with the alleles of Parent 1.

Fill out the squares with the alleles from Parent 2.

The result is the prediction of all possible combinations of genotypes for the offspring of the dihybrid cross, SsYy x SsYy.

There are 9 genotypes for spherical, yellow seeded plants. They are:

SSYY (1/16)
SSYy (2/16)
SsYY (2/16)
SsYy (4/16)

Two recessive alleles result in green seeded plants.

There are 2 genotypes for spherical, green seeded plants. They are:

SSyy (1/16)
Ssyy (2/16)

Two recessive s alleles result in dented seeded plants.

There are 2 genotypes for dented, yellow seeded plants. They are:

ssYY (1/16)
ssYy (2/16)

A ssyy plant would be recessive for both traits.

There is only 1 genotypes for dented, green seeded plants. It is:

ssyy (1/16)